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Calculate the number of the constituent atoms in 53g of Na2CO3.......

Harshit Singh , 4 Years ago
Grade 12th pass
anser 1 Answers
Pawan Prajapati

Last Activity: 4 Years ago

Answer ::

53 g of Na2CO3 Contain = 53106=12 mol.
No of atoms of Na = 12×2×6.022×1023= 6.022×1023.
No of atoms of C = 12×6.022×1023.
No of atoms of O = 12×3×6.022×1023= 9.033×1023.

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