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Grade 12th passPhysical Chemistry

Calculate the number of Faraday`s of electricity required to deposit 60 grams of megnesium

Profile image of Nali papaiah
8 Years agoGrade 12th pass
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1 Answer

Profile image of Chhavi Jain
8 Years ago
Dear student ,
 
Mg2+    +   2e-   ----->  Mg(s)
 
2 mole electrons are required to deposit   ---->24 grams of Mg
       or in other words
To deposit 24g of Mg ----> 2 mole electrons are required  or 2F charge is required
 
So, to deposit 60g of Mg ----->  (2F /24) * 60   charge is required
                                        ------>  5 Faraday (F)  charge is required 
 
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