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Calculate the number of Faraday`s of electricity required to deposit 60 grams of megnesium

Calculate the number of Faraday`s of electricity required to deposit 60 grams of megnesium

Grade:12th pass

1 Answers

Chhavi Jain
92 Points
6 years ago
Dear student ,
 
Mg2+    +   2e-   ----->  Mg(s)
 
2 mole electrons are required to deposit   ---->24 grams of Mg
       or in other words
To deposit 24g of Mg ----> 2 mole electrons are required  or 2F charge is required
 
So, to deposit 60g of Mg ----->  (2F /24) * 60   charge is required
                                        ------>  5 Faraday (F)  charge is required 
 
Chemistry Consultant
Askiitians 

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