Grade 11Physical Chemistry
calculate the no of atoms of constituent element in 53g of NA2CO3
2 Answers
Sheenam
3.011×10^23 atoms (use mole concept)
Atomic mass=avogardo no.
106g of Na2CO3=6.022*10^23atons
53g of Na2CO3=3.011*10^23atoms
khushi singh
Molar mass of Na2CO3 is106g.1 mole=6.022×10^23 particles106g of Na^2CO^3 contain=6.022×10^23molecules1g of Na^2CO^3contain = 6.022×10^23/10653 g of Na^2CO^3 contain=0.056×53×10^23moleculesAns=3.011×10^23molecules
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