Arun
Last Activity: 6 Years ago
boiling point of pure water is 100*C vich is t*b
Bp of solution is given=100.025
w2=1.3g
w1=169g
kb=0.52
putting these values in the formula..
M2=kbxW2x1000 divided by 0.025 x 169
here 0.025 id delta tb. which is obtained by subtracting tb-t*b
= 100.025-100=0.025
after solving ...
676 divided by 4.225 (calculation of values in formula used above)
we get the answer=160gmol-1
Regards
Arun (askIITians forum expert)