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Calculate the mol wt of a substance 1.3 g of which diisolved in 169 g of H2O gave a solution boiling at 100.0250C . Kb forH2O is 5.2 K mol-1, 100 g

Govind Nair , 6 Years ago
Grade 12
anser 1 Answers
Arun

Last Activity: 6 Years ago

boiling point of pure water is 100*C vich is t*b
Bp of solution is given=100.025
w2=1.3g
w1=169g
kb=0.52
putting these values in the formula..
M2=kbxW2x1000 divided by 0.025 x 169
here 0.025 id delta tb. which is obtained by subtracting tb-t*b
= 100.025-100=0.025
after solving ...
676 divided by 4.225 (calculation of values in formula used above)
we get the answer=160gmol-1
 
Regards
Arun (askIITians forum expert)

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