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Calculate the equilibrium constant of the reaction: Cu(s) + 2Ag+(aq) ? Cu2+(aq) + 2Ag(s)

Calculate the equilibrium constant of the reaction: Cu(s) + 2Ag+(aq) ? Cu2+(aq) + 2Ag(s)

Grade:8

1 Answers

Sunil Kumar FP
askIITians Faculty 183 Points
7 years ago
the equilibrium constant of the reaction: Cu(s) + 2Ag+(aq) ---->Cu2+(aq) + 2Ag(s)
The equilibrium constant for the reaction is given by
K=[Cu+2][Ag]^2/[Ag+]^2[Cu]
we have
[Cu](s)=1 and [Ag](s)=1
Therefore the overall equlibrium constant is
K=[Cu+2]/[Ag+]^2

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