Calculate the equilibrium constant of the reaction: Cu(s) + 2Ag+(aq) ? Cu2+(aq) + 2Ag(s)
prasanjeet kumar
12 Years agoGrade 8
1 Answer
Sunil Kumar FP
11 Years ago
the equilibrium constant of the reaction: Cu(s) + 2Ag+(aq) ---->Cu2+(aq) + 2Ag(s) The equilibrium constant for the reaction is given by K=[Cu+2][Ag]^2/[Ag+]^2[Cu] we have [Cu](s)=1 and [Ag](s)=1 Therefore the overall equlibrium constant is K=[Cu+2]/[Ag+]^2