\tCalculate the degree of hydrolysis of a decinormal KCN solution at 25 degree celcius. The dissociation constant of HCN is 7.2 x 10 - 10and ionic product of water is 10 – 14 .\tFind the pH of the solution.
GUNESH PARDESHI , 7 Years ago
Grade 11
1 Answers
Vikas TU
Last Activity: 7 Years ago
The reaction for the dissociation of KCN into the solution is:
KCN + H2O ====> H+ + CN- + OH-
[H+] = [OH-] + [CN-]
[H+]^2 = Ka[HCN] + 10^-14
= 7.2*10^-10*10^-1 + 10^-14
= 72*10^-12 + 0.01*10^-12
[H+] = 72*10^-6 M
pH = -log(72*10^-6) = 4.14
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