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Calculate the de Broglie wavelength for an electron with kinetic energy of 100ev.

Salman Saeed , 8 Years ago
Grade 12th pass
anser 1 Answers
Guru bajrang
LAMDA=h/√2mKE√2mKE=√2×9.1×10*-31×100×1.6×10*-19 =√2912×10*-50 =53.96×10*-25LAMDA= 6.626×10*-31/53.96×10*-25 =0.122×10*-9 =1.22×10*-10 =1.22 ANGSTROMS
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