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Grade 12Physical Chemistry

Calculate the charge in 200gm of water if 10% electros are remove from it

Profile image of Birendra saw
8 Years agoGrade 12
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ApprovedApproved Tutor Answer1 Year ago

To calculate the charge in 200 grams of water after removing 10% of the electrons, we first need to understand the composition of water and the concept of charge associated with electrons. Water (H2O) is made up of two hydrogen atoms and one oxygen atom. Each atom has a specific number of electrons, and when we talk about removing electrons, we are essentially discussing the loss of negative charge.

Understanding the Basics

Water has a molecular weight of approximately 18 grams per mole. This means that in 200 grams of water, we can calculate the number of moles:

  • Moles of water = Mass of water / Molar mass of water
  • Moles of water = 200 g / 18 g/mol ≈ 11.11 moles

Calculating the Number of Molecules

Next, we need to determine how many molecules of water are present in those 11.11 moles. Using Avogadro's number (approximately 6.022 x 10²³ molecules/mole), we can find the total number of water molecules:

  • Number of molecules = Moles of water × Avogadro's number
  • Number of molecules ≈ 11.11 moles × 6.022 x 10²³ molecules/mole ≈ 6.69 x 10²⁴ molecules

Electrons in Water Molecules

Each water molecule contains 10 electrons (2 from hydrogen and 8 from oxygen). Therefore, the total number of electrons in 200 grams of water can be calculated as follows:

  • Total electrons = Number of molecules × Electrons per molecule
  • Total electrons ≈ 6.69 x 10²⁴ molecules × 10 electrons/molecule ≈ 6.69 x 10²⁵ electrons

Removing Electrons

If we remove 10% of these electrons, we first calculate how many electrons that represents:

  • Electrons removed = Total electrons × 10%
  • Electrons removed ≈ 6.69 x 10²⁵ electrons × 0.10 ≈ 6.69 x 10²⁴ electrons

Calculating the Charge

The charge of a single electron is approximately -1.6 x 10⁻¹⁹ coulombs. To find the total charge associated with the removed electrons, we multiply the number of removed electrons by the charge of one electron:

  • Total charge = Electrons removed × Charge of one electron
  • Total charge ≈ 6.69 x 10²⁴ electrons × -1.6 x 10⁻¹⁹ C/electron ≈ -1.07 x 10⁶ coulombs

Final Thoughts

Thus, when 10% of the electrons are removed from 200 grams of water, the total charge associated with those removed electrons is approximately -1.07 million coulombs. This negative sign indicates that the charge is negative, which is consistent with the nature of electrons. Understanding these calculations helps illustrate the relationship between mass, molecular composition, and electrical charge in substances.