Calculate the average of kinetic energy, in joules of the molecules in 8.0 g of methane at 27oC.
Amit Saxena , 10 Years ago
Grade upto college level
Physical Chemistry> Calculate the average of kinetic energy, ...
5 AnswersNavjyot Kalra
Last Activity: 10 Years ago
Total kinetic energy = n (3/2 RT0
where n = Number of moles of the gas
R = Gas constant
T = Absolute temperature
Molecular weight of methane,
CH4 = 12 + 4 * 1 = 16
∴ Number of moles of methane in 8.0 gm of methane
= 8.0/16.0 = 0.5
R = 8.314 joules/K/mole
T = 27 + 273 = 300 K
∴ Total kinetic energy of the molecules in 8.0 gm of methane at 27oC = InI * 3/2 RT
= 0.5 * 3/2 * 8.314 * 300 = 1870.65 joules
∴ Average kinetic energy = 1870.65/6.023 *1023 *0.5
= 6.21 * 10-21 joules/molecule
Prashant
Last Activity: 7 Years ago
Average KE=3RT/2NaWhere R=8.314T=27+273=300kNa=6.023*10^23(avagadros no.)On solving avg KE= 6.21*10^_21
Prashant
Last Activity: 7 Years ago
Average KE=3RT/2NaWhere R=8.314T=27+273=300kNa=6.023*10^23(avagadros no.)On solving avg KE= 6.21 * 10-21 joules/molecule
Parm
Last Activity: 6 Years ago
Average kinetic energy =3RT/Na ×n .......Equation 1 where T = 27+ 273 =300K , R = 8.314 and Na is avogadro number which is = 6.023 × 10^23 and number of moles is 0.5 . put in equation 1 on solving the equation we get average KE = 6.22 × 10^-21
Kushagra Madhukar
Last Activity: 4 Years ago
Dear Student,
Please find the attached solution to your problem.
Total kinetic energy = n 3/2 RT
where n = Number of moles of the gas
R = Gas constant
T = Absolute temperature
Molecular weight of methane,
CH4 = 12 + 4 * 1 = 16
∴ Number of moles of methane in 8.0 gm of methane
= 8.0/16.0 = 0.5
R = 8.314 joules/K/mole
T = 27 + 273 = 300 K
∴ Total kinetic energy of the molecules in 8.0 gm of methane at 27oC = n * 3/2 RT
= 0.5 * 3/2 * 8.314 * 300 = 1870.65 joules
∴ Average kinetic energy = 1870.65/6.023 *1023 *0.5
= 6.21 * 10-21 joules/molecule
Thanks and regards,
Kushagra
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