Calculate ?rG? for conversion of oxygen to ozone, 3/2 O2(g) ? O3(g) at 298 K. if Kp for this conversion is 2.47 × 10–29?

It is the standard free energy which is equal to the difference in free energies of formation of the products and reactants both in their standard states. It is denoted by ΔGo.Relationship between Free Energy and Equilibrium ConstantWhen equilibrium has not been attained, the free energy change of the reaction in any state is denoted as ΔG which is related to the standard free energy change of the reaction, ΔGo.ΔG = ΔGo + RT InQWhere Q is the reaction quotientWhen equilibrium is attained, there is no further free energy change i.e. ΔG = 0 and Reaction quotient Q becomes equal to equilibrium constant. Hence the above equation will become as shown below:ΔGo = –RT In KeqOr ΔGo = –2.303 RT log KeqIn case of galvanic cells. Gibbs energy change ΔG is related to the electrical work done by the cell.ΔG = -nFEcellWhere, n = no. of moles of electrons involvedF = the Faraday constantE = emf of the cellIf reactants and products are in their standard states thenΔGo =nFEocell3/2 O2 (g) ——> O3 (g)Now, ΔGo = –2.303 RT log KpWhere R = 8.314 J/K mol, Kp = 9.4710-29, T = 300KHence Gibbs energy, ΔGo = 160971 J/mol = 160.971 KJ/mol