0

Guest

Courses New

Calculate percentage of purity of h2o2,0.2g of which has been reacted with 20 ml of decimolar kmno4 in acidic medium?

Calculate percentage of purity of h2o2,0.2g of which has been reacted with 20 ml of decimolar kmno4 in acidic medium?

Grade:12th pass

1 Answers

Vikas TU
14149 Points
7 years ago
 2KMnO4 + H2O2 = 2KOH + MnO2 +O2 is the reacn.
Valence factor for KMnO4 => 7 – 4 = +3
Valence factor for H2O2 => +4
Hence moles for H2O2=>
20 * 0.1 * 3 = mmoles of H2O2 * 4
mmoles of H2O2 = 6/4 = 3/2 = 1.5
Weight of H2O2 = > 1.5*10^-3*34 = >  51*10^-3 gms.  => 0.051 gm.
percentage purity = > (0.2 – 0.051)*100/0.2 = > 74.5%

Think You Can Provide A Better Answer ?

Other Related Questions on Physical Chemistry

View all Questions »

ASK QUESTION

Get your questions answered by the expert for free

Answer and earn gift vouchers

Win Gift vouchers upto Rs 500/-

View courses by askIITians

Design classes One-on-One in your own way with Top IITians/Medical Professionals

Click Here Know More

Complete Self Study Package designed by Industry Leading Experts

Click Here Know More

Live 1-1 coding classes to unleash the Creator in your Child

Click Here Know More

a Complete All-in-One Study package Fully Loaded inside a Tablet!

Click Here Know More