Calculate energy of one mole of photons of radiation whose frequency is 5 ×1014 Hz

Hello Students
Energy of one photon is given by the expression E = hV
where, h = PlancKs constant = 6.636 x 10^-34 J s^-1
V= Frequency of radiation = 5x 10¹⁴ Hz= 5 x 10¹⁴ s^-1.
E= (6.636 x 10³⁴ J s-1 x 5 x 10¹⁴ s-1)= 33.18 x 10²⁰J
One mole of photon = 6.023 x 10²³ photons
Therefore, Energy of one mole of photon = (6.023 x 10²³ x 33.18 x 10-²⁰ J) = 199.84 x 10³ J
Energy of one mole of photon = 199.84 kJ

Hello Students

The energy of one photon (E)=hv

Here,h = 6.626×10^-34Js

v = 5×10¹⁴s⁻¹

E = 6.626×10⁻³⁴× 5×10¹⁴
= 3.313×10⁻¹⁹J
Thus the energy of one mole of photons isE×A
Where A is the Avogadro number
= 3.313×10⁻¹⁹J× 6.022×10²³mol^-1

= 199.51 kJmol^-1

I hope this answer will help you.