badge image

Enroll For Free Now & Improve Your Performance.

User Icon
User Icon
User Icon
User Icon
User Icon

Thank you for registering.

One of our academic counsellors will contact you within 1 working day.

Please check your email for login details.

Use Coupon: CART20 and get 20% off on all online Study Material

Total Price: Rs.

There are no items in this cart.
Continue Shopping
Grade: 12


Calculate density of NaCl if edge length of nacl unit cell is 564 pm

2 years ago

Answers : (1)

25236 Points
The volume of a unit cell, Vcell, is given by: 
Vcell = ZM/dN 
where Z is the formula units per unit cell 
M is the molar mass per formula unit 
d is the density in g cm^-3 
N is the Avogadro constant 

NaCl has a fcc lattice and for fcc, Z = 4 
For NaCl, M = 58.44 g mol^-1 

As the unit cell is a cube, the edge length 564 pm = 3√Vcell 
5.64 x 10^-8 cm = 3√(ZM/dN) 
(5.64 x 10^-8 cm)^3 = (ZM/dN) 
dN = ZM/(5.64 x 10^-8 cm)^3 
d = [ZM/(5.64 x 10^-8 cm)^3]/N 
d = [(4 x 58.44 g mol^-1)/(5.64 x 10^-8 cm)^3)]/6.022 x 10^23 mol^-1 
d = 2.16 g cm^-3
2 years ago
Think You Can Provide A Better Answer ?
Answer & Earn Cool Goodies

Course Features

  • 731 Video Lectures
  • Revision Notes
  • Previous Year Papers
  • Mind Map
  • Study Planner
  • NCERT Solutions
  • Discussion Forum
  • Test paper with Video Solution

Course Features

  • 141 Video Lectures
  • Revision Notes
  • Test paper with Video Solution
  • Mind Map
  • Study Planner
  • NCERT Solutions
  • Discussion Forum
  • Previous Year Exam Questions

Ask Experts

Have any Question? Ask Experts

Post Question

Answer ‘n’ Earn
Attractive Gift
To Win!!! Click Here for details