Calculate density of NaCl if edge length of nacl unit cell is 564 pm
abhinab , 6 Years ago
Grade 12
Physical Chemistry> Calculate density of NaCl if edge length ...
1 Answers
Arun
Last Activity: 6 Years ago
The volume of a unit cell, Vcell, is given by:
Vcell = ZM/dN
where Z is the formula units per unit cell
M is the molar mass per formula unit
d is the density in g cm^-3
N is the Avogadro constant
NaCl has a fcc lattice and for fcc, Z = 4
For NaCl, M = 58.44 g mol^-1
As the unit cell is a cube, the edge length 564 pm = 3√Vcell
5.64 x 10^-8 cm = 3√(ZM/dN)
(5.64 x 10^-8 cm)^3 = (ZM/dN)
dN = ZM/(5.64 x 10^-8 cm)^3
d = [ZM/(5.64 x 10^-8 cm)^3]/N
d = [(4 x 58.44 g mol^-1)/(5.64 x 10^-8 cm)^3)]/6.022 x 10^23 mol^-1
d = 2.16 g cm^-3
Vcell = ZM/dN
where Z is the formula units per unit cell
M is the molar mass per formula unit
d is the density in g cm^-3
N is the Avogadro constant
NaCl has a fcc lattice and for fcc, Z = 4
For NaCl, M = 58.44 g mol^-1
As the unit cell is a cube, the edge length 564 pm = 3√Vcell
5.64 x 10^-8 cm = 3√(ZM/dN)
(5.64 x 10^-8 cm)^3 = (ZM/dN)
dN = ZM/(5.64 x 10^-8 cm)^3
d = [ZM/(5.64 x 10^-8 cm)^3]/N
d = [(4 x 58.44 g mol^-1)/(5.64 x 10^-8 cm)^3)]/6.022 x 10^23 mol^-1
d = 2.16 g cm^-3
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