Grade 6Physical Chemistry

By analyzing separately two different oxides of the same material, it was found that in one of them it had 16 g of oxygen combined with 56 g of a metal, while the other contained a mass m combined with 48 g of oxygen. Taking into account Dalton's law, calculate the mass m.

Dirceu Reforco Escolar

8 Years agoGrade 6

6 Answers

Nikhil

8 Years ago

Dear friend,

On simply analysing we can say that first oxide is FeO as molecular mass of Fe is 56 and that od oxygen is 16. In the same way we can say that the another one is Fe₂O₃ as 2Fe is combined with 3O having mass 48 .

So the correct answer should be 102g

Dirceu Reforco Escolar

8 Years ago

But, the answer is 112 g. And I do not know how to make that answer. And I do not know how to explain it according to Dalton's Law

Dirceu Reforco Escolar

8 Years ago

But, the answer is 112 g. And I do not know how to make that answer. And I do not know how to explain it according to Dalton's Law

Subhash Kumar Mehta

8 Years ago

we observe that 16g of O and 56g of material is present in one oxide so no of O present is 1 and another material will have atomic mass factor of 56 so it will be Fe also in other oxide m mass of Fe is present and 48g O presentNow carried frwd.......

Subhash Kumar Mehta

8 Years ago

Now from law of multiple proportion let first oxide be FeO we write 2FeO and second oxide as FenO3(n is no of Fe atom) so mass of Fe should be fixed so as to obtain the ratio of O simple whole no. i.e., 1:3 hence carried forward.........

Subhash Kumar Mehta

Approved Tutor Answer8 Years ago

.......Hence the value of n should be 2 and Fe2 is present in another oxide therefore m=mass of 2 atoms of Fe m=2*56 m=112g Ans»Thanks »Regards»Subhash Kumar»St. Xavier`s College, Ranchi