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Grade: 11

                        

At 340K 1atm pressure N2O4 is 66% dissociated into NO2.what is volume of 10g of N2O4 occupy under these conditions

2 years ago

Answers : (1)

Arun
24742 Points
							
N2O4(g) 2NO2(g) 
10.0g 
T = 340K 
P = 1.00atm 

Assuming we started with 10.0g of N2O4 and, 66% of it decomposed, that will leave 3.4g of N2O4, and make 6.6g of NO2. Convert those to moles, and then plug them into the ideal gas equation. 

At equilibrium.... 
3.4 g N2O4 .... 0.03696 mol N2O4 ...... carry extra sig figs for intermediate answers 
and 
6.6g NO2 ....... 0.1435 mol NO2 

Total moles = 0.1805 moles of N2O4 and NO2, at a total pressure of 1.00 atm. Find the volume. 

PV = nRT 
V = nRT / P = 0.1805 mol x 0.0821Latm/molK x 340K / 1.00 atm = 5.04L 

You will get 5.02L if you use 0.18 moles of gas
2 years ago
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