Create your Smart Home App in the Free Webinar on Home Automation. Register Now
One of our academic counsellors will contact you within 1 working day.
Click to Chat
1800-1023-196
+91-120-4616500
CART 0
Use Coupon: CART20 and get 20% off on all online Study Material
Welcome User
OR
LOGIN
Complete Your Registration (Step 2 of 2 )
Free webinar on App Development Learn to create your own Smart Home App
16th Jan @ 5:00PM for Grade 1 to 10
Sit and relax as our customer representative will contact you within 1 business day
At 340K 1atm pressure N2O4 is 66% dissociated into NO2.what is volume of 10g of N2O4 occupy under these conditions
N2O4(g) 2NO2(g) 10.0g T = 340K P = 1.00atm Assuming we started with 10.0g of N2O4 and, 66% of it decomposed, that will leave 3.4g of N2O4, and make 6.6g of NO2. Convert those to moles, and then plug them into the ideal gas equation. At equilibrium.... 3.4 g N2O4 .... 0.03696 mol N2O4 ...... carry extra sig figs for intermediate answers and 6.6g NO2 ....... 0.1435 mol NO2 Total moles = 0.1805 moles of N2O4 and NO2, at a total pressure of 1.00 atm. Find the volume. PV = nRT V = nRT / P = 0.1805 mol x 0.0821Latm/molK x 340K / 1.00 atm = 5.04L You will get 5.02L if you use 0.18 moles of gas
Post Question
Dear , Preparing for entrance exams? Register yourself for the free demo class from askiitians.
points won -