Grade 11Physical ChemistryAt 300K, 5% glucose and 1.1% Kcl solution are isotonic. Calculate the degree of dissociation of Kcl. Percentage given is in mass/volume Saurav Raj 9 Years agoGrade 11
Vikas TU9 Years agoFor Glucose,1xC1xSxT = ixC2xSxTC1 = (5/180)*1000/100and C2 = (1.1/111)*1000/100 (5/180)*1000/100 = i*(1.1/111)*1000/1000.099i = 0.277i = 2.805 Degree of dissociation=>KCl =============> K+ + Cl-C0 0 0C0(1-a) C0a C0aa => (2.805 – 1)*100/2.805 => 64.3%