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at 27 degree c, 500ml of helium diffuse inj 30 min. what is the time taken for 100ml of so2 to diffuse under same experimental conditions

at 27 degree c, 500ml of helium  diffuse inj 30 min. what is the time taken for 100ml of so2 to diffuse under same experimental conditions

Grade:9

1 Answers

Arun
25750 Points
4 years ago
From Graham's law of diffusion , the rate of diffusion of a gas is inversely proportional to the square root of its molar mass.
⇒ r ∞ 1/ √M
⇒ r = k/√M        where , k is a constant
Also r = V/t  i/e rate of diffusion of volume of gas
Now ,
Molar mass of He = M₁ = 4 gm
Volume = V₁ = 500 ml 
t₁ = 30 mins
Molar mass of SO₂ = M₂ = 64 gm
Volume = V₂ = 100 ml 
t₂ = ? 
rate of diffusion of Helium = r₁  = V₁/t₁  = 500/30 ml/mins
r₂ = 100/t₂ 
r₁ = k/√M₁        and      r₂ = k/√M₂
r₁ / r₂ = k/√M₁ / k /√M₂ = 500/30/100/t₂ 
t₂ = 24 mins 
 
Regards
Arun (askIITians forum expert)
 

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