Grade 12th passPhysical ChemistryAt 250 degree C the vapour density of PCl5 is 100 calculate the degree of disociation at this temperature ? bhargav 9 Years agoGrade 12th pass
Vikas TU9 Years ago The Reaction for the PCl5 is:PCl5 ====> PCl3 + Cl2n = 1 + 1 = 2Now the degree of dissociation related o the theoretical mass and the observed mass is:a = (Mth – Mobs.)/Mth.(n -1)a = (208.24 – 200)/(208.4*(2-1)) => 0.039 or 3.9% disscocitaion.