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At 25*C , the solubility product of Mg(OH)2 is (1.0 X 10 to the power -13) . At which pH, will Mg+2 ions start precipitating in the form of Mh(OH)2 from a solution of 0.001M Mg+2 ions?? 1 8 9 10
@kaustabh i am giving u the correct approach to solve the question .. as u knws the formula to calculate the olubility constant ksp = c ^ 2s square c is given as 10 to the power -3 then P (oh ) = loh ( oh ) – apply that equation and u will get the answer / option no c turns out to be the correct option . so, answer is 9 . HOPE U CAN DO IT AL;L THE BEST ..
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