At 100C and at 1atm, if the vapour density of the liquid water is 1gcm/3 and that of water vapour is 0.0006g/cm3 then the volume occupies by water molecules in 1L of stream at this temperature will be?

To find the volume occupied by water molecules in 1 liter of steam at 100°C and 1 atm, we must first understand the relationship between the density of the vapor and the volume. Given that the vapor density of steam (water vapor) is 0.0006 g/cm³, we can start our calculations from this point.

Understanding the Concept of Density

Density is defined as mass per unit volume. The formula for density can be expressed as:

Density = Mass / Volume

This means that if we know the density of a substance, we can rearrange this equation to find the volume if we have the mass:

Volume = Mass / Density

Calculating the Mass of Water Vapor in 1 Liter

We need to convert 1 liter of steam into cubic centimeters, since the density is given in g/cm³. Knowing that 1 liter is equal to 1000 cm³, we can now proceed with our calculations:

Volume of steam = 1000 cm³

Next, we calculate the mass of water vapor in this volume using the provided vapor density:

Mass = Volume × Density

Substituting the values:

Mass = 1000 cm³ × 0.0006 g/cm³ = 0.6 g

Finding the Volume Occupied by Water Molecules

Now that we have the mass of the steam, we can find out how much volume the water molecules occupy based on the density of liquid water. The density of liquid water is given as 1 g/cm³. Using the same volume formula, we can find the volume occupied by the water molecules:

Volume of water = Mass / Density of water

Substituting the mass we found:

Volume of water = 0.6 g / 1 g/cm³ = 0.6 cm³

Conclusion

In summary, in 1 liter of steam at 100°C and 1 atm, the volume occupied by water molecules is 0.6 cm³. This small volume is a reflection of the low density of water vapor compared to its liquid form, illustrating the significant difference in space occupied by substances in their gaseous and liquid states.