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```         At 100°C and 1 atm if the density of the liquid water is 1.0 g cm-3 and that of water vapour is 0.0006 g cm-3, then the volume occupied by water molecules in 1 L of steam at this temperature is
a. 6 cm3
b. 60 cm3
c. 0.6 cm3
d. 0.06 cm3
```
5 years ago

Navjyot Kalra
654 Points
```							sol. Let us consider, 1.0 L of liquid water is converted into steam volume of H2O (l) = 1 L, mass = 1000 g
⇒ Volume of 1000 g steam = (1000 )/0.0006 cm3
∵ Volume of molecules in (1000 )/0.0006 cm3 steam = 1000 cm3
∴ Volume of molecules in
1000 cm3 steam = (1000 )/1000 × 0.0006 × 1000
= 0.60 cm3

```
5 years ago
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### Course Features

• 141 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions