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Adil Grade: 12
        Aqueous solution of uria of freezing point is 0.4°c. What will be boiling point this solution (Kf=3.632Kb)
one year ago

Answers : (1)

Vikas TU
6872 Points
										
Tf = iKfm
0.4 = 1*3.632Kb*m
 
Boiling Point,
Tb = 1*Kb*m
Dividing both eqns. we get,
0.4/Tb = 3.632
Tb = 0.4/0.3632 => 1.10132 ‘C
one year ago
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