Aqueous solution of uria of freezing point is 0.4°c. What will be boiling point this solution (Kf=3.632Kb)

Question

Vikas TU · Answer

Tf = iKfm 0.4 = 1*3.632Kb*m Boiling Point, Tb = 1*Kb*m Dividing both eqns. we get, 0.4/Tb = 3.632 Tb = 0.4/0.3632 => 1.10132 ‘C

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Aqueous solution of uria of freezing point is 0.4°c. What will be boiling point this solution (Kf=3.632Kb)

Aqueous solution of uria of freezing point is 0.4°c. What will be boiling point this solution (Kf=3.632Kb)

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Aqueous solution of uria of freezing point is 0.4°c. What will be boiling point this solution (Kf=3.632Kb)

Aqueous solution of uria of freezing point is 0.4°c. What will be boiling point this solution (Kf=3.632Kb)

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