Grade 12Physical ChemistryAqueous solution of uria of freezing point is 0.4°c. What will be boiling point this solution (Kf=3.632Kb) Adil 9 Years agoGrade 12
Vikas TU9 Years agoTf = iKfm0.4 = 1*3.632Kb*m Boiling Point,Tb = 1*Kb*mDividing both eqns. we get,0.4/Tb = 3.632Tb = 0.4/0.3632 => 1.10132 ‘C