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Apiece of iron gains 10% of it’s weight due to partial rusting into Fe 2 O 3 the percentage of total iron that has rusted is?
The reacn. of rusting => 2Fe + 3/2 O2 -------------> Fe2O3 x/56 11x/1600% = > (x)/(11x*2*56/1600) * 100 => 77%
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