Vikas TU
Last Activity: 5 Years ago
Dear student
Angular momentum of 2nd Bohr orbit is x.
So, L = nh/2π = 2h/2π = h/π
For, Li2+, it is 2st excited state. This also means that n = 2.
As angular momentum does not depend on atomic number,
So, L = nh/2π = 2h/2π = h/π
Thus angular momentum of both the systems are same, i.e. x
The answer is x.