An organic compound on analysis gave the following data:C = 57.82%H = 3.6%O = 38.58%Find its empirical formula.Pls answer with solution

answer is C₄H₃O₂ 

First you have to convert C/H/O in to grams ,that is C=57.82 gm / H=3.6 grams / O=38.58 gm 

then divide it by the actual molar mass of the element , that is C 57.82 ÷ 12 = 4.81 / H  3.6 ÷ 1 = 3.6 / O 38.58÷16 = 2.41

FIND THE LEAST VALUE  { here it’s oxygen with 2.41 }
again divide C = 4.81÷(LEAST VALUE)  = 1.99 {TAKE IT AS IN ROUND FIGURE (2)}
lly H = 3.6÷(LEAST VALUE) = 1.49 {1.5}
lly O = 2.41÷2.41 = 1
NOW see carefully we got a value of  H=1.5 which is not suitable for emperical formula
so we have to multiply a whole no {here we multiply with 2}
C = 2×2 = 4 ATOMS
H =1.5x2 = 3 ATOMS
O = 1x2 = 2 ATOMS
ANSWER = C4H3O2