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An ion with mass no. 56 contain 3 positive charge . If ion contain 30.4% more neutrons than the electrons??
Let the number of electrons in ion = XNumber of proton or atomic number of element = X+3Number of neutrons in ion = X + 30.4% of X = X + 0.304 X=1.304 X Atomic mass of an element is sum of the number of neutrons and number of protons of the element.thus56 = (X+3) +(1.304 X) orX = 23Hence Atomic number of the element is 23+3 = 26, and the element is Fe,The ion is Fe3+
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