Grade upto college level Physical Chemistry

An insulated container contains 1 mol of a liquid, molar volume 100 ml, at 1 bar. When liquid is steeply pressed to 100 bar, volume decreases to 99 ml. Find. ∆H and ∆U for the process.

Shane Macguire

12 Years agoGrade upto college level

12 Years ago

Hello Student,

Please find the answer to your question

For adiabatic process, W = P (V₂ – V₁)

Here P₁ = 1 bar, P₂= 100 bar, V₁ = 100 mL, V₂ = 99 mL; For adiabatic process, q = 0 / ∆U = w

∆U = q + W

= q – P(V₂ – V₁) since W = - P(V_{2= - V}1)

= 0 – 100 (99 - 100) = 100 bar mL

∆H = ∆U + ∆(PV) = ∆U + (P₂V₂ – P₁V₁)

100 + [(100 * 99) – (1 * 100)]

= 100 + (9900 - 100) = 9900 bar mL

Thanks
Deepak patra
askIITians Faculty

physical chemistry

0 Answer Available

Last Activity: 3 Years ago

physical chemistry

Last Activity: 3 Years ago

physical chemistry

Last Activity: 3 Years ago

physical chemistry

Last Activity: 4 Years ago

physical chemistry

Last Activity: 4 Years ago