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Physical Chemistry

An H atom has been excited to 4 d(x^2-y^2) orbital. What is the maximum number of lines it can emit during deexcitation?
A)3 B)6 c)17 d)9
Please explain and thank you

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7 Years agoGrade
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ApprovedApproved Tutor Answer7 Years ago

generalised formula is

n=(n*-n°)(n*-n°+1)/2

Where n* is the higher level or the level from which electron jumps and n° is the lower level where electron jumps.


hence by formula, number of emission lines = 3*4/2 = 6