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Grade: 12th pass

                        

An evacuated observation balloon after filling with helium gas had an increase in weight equal to 2 g. The volume of the balloon at STP must be?

3 years ago

Answers : (2)

THANGUTURU NIRGUNA
20 Points
							
STP value is 22.4 litres.then there is a balloon weight 2 grams.then we have yo multiply the weight *stp value
22.4*2=44.8litres
3 years ago
Yogita Negi
28 Points
							
volume=
moles = volume at STP condition/molar volume
i.e. 2/4 = vol./22.4
= 2/4*22.4
= 11.2 L            ...check out this ans.
 
one year ago
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