Arun
Last Activity: 7 Years ago
At temperature 300 K, the internal pressure inside the bulb is solely due to the Ne gas, hence it follows the expression:
P300K = (nNe RT) / V ----- (1)
At temperature 600 K, the NH4Cl dissociates into NH3 and HCl, hence the total pressure inside the bulb will be due to the presence of Ne, NH3 and HCl gases, hence
P600K = ((n1 + nNe) RT) / V ------(2) [where n1= nNH3 + nHCl]
Dividing expression (1) by (2) we get,
114/908 = 0.01/(n1+ 0.01)
n1 = 0.07
Since NH4Cl dissociates into equal molar amounts of NH3 and HCl, the nNH3 and nHCl = 0.07 / 2 = 0.035 moles each
partial pressure of NH3 = mole fraction of NH3x P600K
PNH3 = 0.35 *908/0.35 +0.35 +0.01
= 397 mmHg
