An element X with an atomic mass of 60g/mol has density of 6.23g cm-3. If the edge length of its cubic unit cell is 400 pm, identify the type of cubic unit cell. Calculate the radius of an atom of this element.-?
Prakash pandey
12 Years agoGrade 12
2 Answers
Sunil Kumar FP
11 Years ago
we have density d=ZM/a^3Na Z=no of atom to calculate M is the molecular mass Na is the avagadro constant a is the edge length Z=(d*a^3Na)/M =6.23*(4*10^-8)^3*6*10^23/60 =4 Therefore th unit cell is FCC. and the length of the unit cell is sqrt2 a=4*radius=sqrt2/4*400pm=141.4pm
ankit singh
5 Years ago
An element x with an atomic mass of 60 g/mol has density of 6.23 g/cm3. If the edge length of the unit cell is 400 pm, identify the type of cubic unit cell. ... ∴ Z=4 Hence, it is face-centred cubic unit cell.