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An element undergoes a reaction as shown, X+2e- --------> X2- Energy released=30.87eV/atom.If the energy released is used to dissociate 4g of H2 molecules,equally into H+ and H*, where H* is the excited state of H atoms where the electron travels in orbit whose circumference equal to four times it's de Brogllie's wavelength.Determine the least moles of X that would be required: Given I.E.of H=13.6eV/atom,bond energy of H2 =4.526eV/molecule.
An element undergoes a reaction as shown,            X+2e- --------> X2-Energy released=30.87eV/atom.If the energy released is used to dissociate 4g of H2 molecules,equally into H+ and H*, where H* is the excited state of H atoms where the electron travels in orbit whose circumference equal to four times it's de Brogllie's wavelength.Determine the least moles of X that would be required:Given I.E.of H=13.6eV/atom,bond energy of H2 =4.526eV/molecule.

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2 years ago

## Answers : (1)

Avni Chauhan
247 Points
```							Here, each molecule of H21.)dissociates (this requires bond dissociation enthalpy) into2)H+(for which we require ionization enthalpy) and3)H*(which is the excited H atom)  this atom is in the fourth state. Energy in this state = 13.6/n2= 13.6/16  therefore energy supplied = 13.6 – (13.6/16) = (15/16) 13.6And we have a total of 4g H2molecules means 2NamoleculesTherefore energy required == 2 * 6.022*1023(B.D.E + I.E. + energy for excitation)=2 * 6.022*1023 (4.526 + 13.6 + (15/16) 13.6)= (2 * 6.022*1023* 30.876) eVThis energy is supplies by atoms of X. Energy released per atom = 30.87eV /atomso, atoms required = 2* 6.022*1023= 2 moles
```
2 years ago
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