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Physical Chemistry

An element crstallizes in a fcc structure with atomic mass 60 g/mol. Calculate its edge lenght.

[given, anagadro's Number = 6.02 * 10^23 mol^-1]

Answer is 10.40 pm(pico moeter).

How this is to be solve. Please tell me its Important for me.

Profile image of Kabir Thapar
12 Years agoGrade
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1 Answer

Profile image of Sunil Kumar FP
12 Years ago
dear friend if i am not wrong please read the uestion carefully.you have not provided the density of the element because without it it cannt be solved.
use the formula density ¥=z×m/a3×Na
z=no of atom for fcc itis 4
m=massno=60
a=edge length
Na=avagadro no

thanks and regard
sunil kumar
askiitian faculty