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`        An aqueous solution contains 1 mole of urea and 1kg of water. Kf for water is 1.8 kg/mol. Calculate the amount of ice seperated from the solution at -3.6°C.`
one year ago

Vikas TU
9762 Points
```							From T = i*Kf*mi = 1kf = 1.8 kg/mol T = 0- (-3.6) = 3.6 3.6 = 1.8*mm = 2m’ = moles of urea/mass of solvent in kg => 1/1 = 1m – m’ = 2-1 = 11 = w/18w = 18 gms of ice has been separated.
```
one year ago
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