An aqueous solution contains 1 mole of urea and 1kg of water. Kf for water is 1.8 kg/mol. Calculate the amount of ice seperated from the solution at -3.6°C.

Question

Vikas TU · Answer

From T = i*Kf*m i = 1 kf = 1.8 kg/mol T = 0- (-3.6) = 3.6 3.6 = 1.8*m m = 2 m’ = moles of urea/mass of solvent in kg => 1/1 = 1 m – m’ = 2-1 = 1 1 = w/18 w = 18 gms of ice has been separated.

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An aqueous solution contains 1 mole of urea and 1kg of water. Kf for water is 1.8 kg/mol. Calculate the amount of ice seperated from the solution at -3.6°C.

An aqueous solution contains 1 mole of urea and 1kg of water. Kf for water is 1.8 kg/mol. Calculate the amount of ice seperated from the solution at -3.6°C.

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An aqueous solution contains 1 mole of urea and 1kg of water. Kf for water is 1.8 kg/mol. Calculate the amount of ice seperated from the solution at -3.6°C.

An aqueous solution contains 1 mole of urea and 1kg of water. Kf for water is 1.8 kg/mol. Calculate the amount of ice seperated from the solution at -3.6°C.

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