Flag Physical Chemistry> An aqueous solution containing 0.01 g KIO...
question mark

An aqueous solution containing 0.01 g KIO3 (formula weight = 214.0) was treated with an excess of KI solution. The solution was acidified with HCI. The liberated I2 consumed 45.0 mL of thiosulphate solution decolourise the blue starch-iodine complex. Calculate the molarity of the sodium thiosulphate solution.

Amit Saxena , 10 Years ago
Grade upto college level
anser 1 Answers
Jitender Pal

Last Activity: 10 Years ago

Sol. The redox reaction involved are : 〖IO〗_3^- + 5I- + 6H+ → 3I2 + 3H2O I2 + 2S2O_3^(2-) → 2I- + S4O_6^(2-) Millimol of KIO3 used = 0.1/214 × 1000 = 0.467 ⇒ millimol of I2 formed = 3 × 0.467 = 1.4 ⇒ millimol of Na2S2O3 consumed = 2 × 1.4 = 2.8 ⇒ Molarity of Na2S2O3 = 2.8/45 = 0.062 M

Provide a better Answer & Earn Cool Goodies

Enter text here...
star
LIVE ONLINE CLASSES

Prepraring for the competition made easy just by live online class.

tv

Full Live Access

material

Study Material

removal

Live Doubts Solving

assignment

Daily Class Assignments


Ask a Doubt

Get your questions answered by the expert for free

Enter text here...