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. An alloy of copper , gold and silver is found to have Cu atoms forming simple cubic lattice . If Ag atoms occupy all the face centres and Au atoms at body centres what is the simplest formula of the alloy?
Cu = 8*1/8 = 1 (SCC)Ag = 6*1/2 = 3 (FCC)Au = 1(Body Centre)Hence the formulae would become:CuAg3Au
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