. An alloy of copper , gold and silver is found to have Cu atoms forming simple cubic lattice . If Ag atoms occupy all the face centres and Au atoms at body centres what is the simplest formula of the alloy?

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Vikas TU · Answer

Cu = 8*1/8 = 1 (SCC) Ag = 6*1/2 = 3 (FCC) Au = 1(Body Centre) Hence the formulae would become: CuAg3Au

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. An alloy of copper , gold and silver is found to have Cu atoms forming simple cubic lattice . If Ag atoms occupy all the face centres and Au atoms at body centres what is the simplest formula of the alloy?

. An alloy of copper , gold and silver is found to have Cu atoms forming simple cubic lattice . If Ag atoms occupy all the face centres and Au atoms at body centres what is the simplest formula of the alloy?

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. An alloy of copper , gold and silver is found to have Cu atoms forming simple cubic lattice . If Ag atoms occupy all the face centres and Au atoms at body centres what is the simplest formula of the alloy?

. An alloy of copper , gold and silver is found to have Cu atoms forming simple cubic lattice . If Ag atoms occupy all the face centres and Au atoms at body centres what is the simplest formula of the alloy?

1 Answers

Think You Can Provide A Better Answer ?

Other Related Questions on Physical Chemistry

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