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Grade 12th passPhysical Chemistry

AIPMT 2012M Q31 Please provide a detailed solution.......

Question image for AIPMT 2012M Q31 Please provide a detailed solution
Profile image of ANMOL SETH
9 Years agoGrade 12th pass
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1 Answer

Profile image of Bhavya
9 Years ago
Dear student
We know that,

\DeltaG = -nFE
Here n= 4
O32- (From Al2O3) -----> O20
change of electron in 1 mole is 2*3 = 6
but i have 2/3 moles of Al2O3 therefore change in electrons = 6*2/3 = 4

960*1000 = -4*96500*E
E = 2.48 V\sim2.5 V