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Addition of CdCl2 to AgCl yields solid solution where the divalent cations Cd2+ occupy the Ag+ sites. Which one of the following statements is true?\tThe no. of cationic vacancies is equal to that of divalent ions added.\tThe no. of cationic vacancies is one half of the no. of that of divalent ions added.\tThe no. of anionic vacancies is equal in no. to that of divalent ions added\tNo cationic or anionic vacancies are produced.

Shibashis Mallik , 9 Years ago
Grade 12
anser 1 Answers
Pankaj

Last Activity: 9 Years ago

Each Cs2+ ions replaces two Ag+ ions. One of the two vacant sites is occupied by Cd2+ ion while other remains vacant resulting into p type vacancy.
So the number of cationic vacancies is equal to that of divalent ion added.

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