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Grade: 12
        
 A voltaic cell is set up at 25°C with the following half cells:
Ag* (0.001 M )|Ag and Cu2+(0. 10 M)| Cu.What would be the voltage of this cell? ( E cell°=0.46V)
 
25 days ago

Answers : (1)

Mayank
368 Points
							
as Cu can reduce Ag+ to Ag and can be oxidised into Cu+2 so we have the equation as
   Cu  +      2Ag  -------->   2Ag   +    Cu+2 
                           0.001M                               0.1M        
  
using the equation E  =  E  –  0.0591*ln(anode conc./cathode conc.)/n      where n=no. of electrons involved  
so putting anode conc. = 0.1M   and cathode conc. =0.001M  and E=0.46  we get E= 0.31225
24 days ago
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