MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping
Menu
Grade: 11
        
A vertical hollow cylinder of height 1.52m is fitted with a movable piston of negligible mass and thickness l.the lower half of the cylinder contains an ideal gas and the upper half is filled with mercury .the cylinder is initially at 300k.when the temperature is raised half o the mercury comes out of the cylinder. Find the temperature assuming the thermal expansion of mercury to be negligible
 
 
23 days ago

Answers : (1)

Vikas TU
8383 Points
							
Dear student 
Pressure of gas = pressure of Hg(mercury) + pressure of atmospheric air
Pressure of Gas = 76 cm of Hg + 76 cm of air.
Pressure of Gas P₁ = 152 cm.  Cylinder initial  (T₁) = 30  V = V₁ /2 , here V₁ is the volume of the cylinder.  V = 76/2 =38
After heating ,  Pressure of Gas = Pressure of Hg + Pressure of Atmospheric air
= 38 + 76
P₂= 114 cm.   , V₂ = 3V₁ /4
Now applying the Gas equation .    
= (152 x V₁) / 2 x 300 = [144 x (3V₁/4) ] / T₂
= (300 × 2 × 3 × 114) / 152 × 4
T₂ = 337.5 
 
23 days ago
Think You Can Provide A Better Answer ?
Answer & Earn Cool Goodies


Course Features

  • 731 Video Lectures
  • Revision Notes
  • Previous Year Papers
  • Mind Map
  • Study Planner
  • NCERT Solutions
  • Discussion Forum
  • Test paper with Video Solution


Course Features

  • 141 Video Lectures
  • Revision Notes
  • Test paper with Video Solution
  • Mind Map
  • Study Planner
  • NCERT Solutions
  • Discussion Forum
  • Previous Year Exam Questions


Ask Experts

Have any Question? Ask Experts

Post Question

 
 
Answer ‘n’ Earn
Attractive Gift
Vouchers
To Win!!! Click Here for details