Question icon
Grade 8Physical Chemistry

A solution of CuSO4 is electrolysed for 10 minutes with a current of 1.5 amperes. What is the mass of copper deposited at the cathode?

Profile image of prasanjeet kumar
12 Years agoGrade 8
Answers icon

4 Answers

Profile image of Gaurav
11 Years ago
255-989_Capture.PNG
Profile image of Akash
7 Years ago
estimate the mass of copper metal produced during passage of 5A current through CuSO4 solutions for 100 min (the molar mass of Cu is 63.5g/mol.)
Profile image of Punit
7 Years ago
Here,Charge available Q is,
Q=5*6000=30000C
But as we know,that here in this question
2*96500C=63.5g
1C=63.5/2*96500
30000C= 63.5*30000/2*96500
Profile image of Rishi Sharma
6 Years ago
Hello Prasanjeet,
The solution is as follows
The cathodic reaction is
Cu2+ + 2e- → Cu
I = 1.5 A
t = 10 min = 10*60 = 600 sec
reaction states that 2 * 96500 C requires to deposit 63.5 g of Cu at cathode
for 900 C will deposit = 63.5 * 900 / (2 * 96500 )
= 0.296 g

Thanks
I hope above solution will clear your all doubts.
Please feel free to post and ask as much doubts as possible.
All the best.