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Grade 12Physical Chemistry

A solution is prepared by mixing 8.5 g of CH2Cl2
and 11.95 g of CHCl3
. If vapour pressure of CH2Cl2
and CHCl3
at 298 K are 415 and 200 mm Hg respectively, the mole fraction of CHCl3
in vapour
form is : (Molar mass of Cl = 35.5 g mol–1)

Profile image of vibhuti raj
7 Years agoGrade 12
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1 Answer

Profile image of Aastha Singh
7 Years ago
Dear Student,
the total vapour pressure in the question is missing,
apply formula :
vapour pressure of 1 gas=total vapour pressure*moles of gas1/moles of gas 1+ moles of gas 2