Dear Student,
The reaction is
2 KmnO4+ 3 H2SO4 = K2SO4 + 2 MnSO4 +3H2O+ 5[O]
H2O2+ [O] à H2O + O2. X5
Hence 2 KmnO4 = 5 H2O2
If the sample is of 1 gram KmnO4 reqired is = 2x158/ (5x34) =1.86 gram.
So, normality is 1.86x10/31.6 = 0.58
Molarity is 0.58/5 = 0.116.
Cheers!!
Regards,
Vikas (B. Tech. 4th year
Thapar University)