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a sample of drinking water was found to be severely contaminated with chloroform CHCl 3 supposed to be a carcinogen the level of contamination was 15ppm by mass
1. express this in % mass
2. determine the molality of chloroform in the water sample
7 months ago

Dear student

1) 15 ppm means 15 parts in 1 millions (10^6)
and percentage always for 100

hence 15 ppm = (15/10^6 )*100
= 15*10^-4
= 1.5*10^-3
2) molar mass of chloroform = 118.5g/ mol

from percentage by mass 100 gram of sample has 1.5*10^-3 g of chloroform
then 1000 gram of sample has = 1.5*10^-3 g * 1000 gram/ 100 gram
= 1.5*10^-2 g

molality = moles of solute / mass of solvent in Kg

moles of solute = mass of solute / molar mass
= 1.5*10^-2/ 118.5
=1.266*10^-4 moles

molality =  1.266*10^-4 moles/ 1 Kg =1.266*10^-4 m

Regards
Arun
7 months ago

Dear Aiden,
PPM refers to parts per million or (mass of chloroform) x  divided by the total mass--Equation 1
Mass percentage refers to the mass of chloroform x  divided by the total mass--Equation 2
So dividing Equation 2 by Equation 1 we get
Mass percentage =   =
Now molality is defined as the ratio of the number of moles of solute divided by the mass of solvent in kg
The molecular mass of chloroform or mass of 1 mole of chloroform is 119.38 g/mol (you may round it off as 119.5 or 120 g/mol as required)
Now out of 100g of the solution, the mass of chloroform is  g
So the mass of solvent =  g = 99.9985 g (You may round it off as 100 g)
= 0.0999985 kg (can be rounded off to 0.1 kg)
Now the number of moles of chloroform =
So molality =  mol/kg
mol/kg
Hope this helps!
regards,
Soumendu

7 months ago
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