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A reaction is of first order in reactant A and of second order in reactant B. How is the rate of this reaction affected when (i) the concentration of B alone is increased to three times (ii) the concentrations of A as well as B are doubled?

 A reaction is of first order in reactant A and of second order in reactant B. How is the rate of this reaction affected when (i) the concentration of B alone is increased to three times (ii) the concentrations of A as well as B are doubled? 

Grade:12

2 Answers

Nicho priyatham
625 Points
8 years ago
i)the rate becomes 9 times
ii)the rate becomes 8times
plz approve if useful
grenade
2061 Points
8 years ago
It is given that a reaction is first order in reactant A and second order in reactant B 
rate = k[a][b] square
where r is the rate of reaction and k is the rate constant of the reaction 
now on equating we will get the value equals 9
 
similarly in second we will get the value as 8

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