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A neutron.
We use the de Broglie expression:
λ=hmv
So we can write:
λe=hmeve (1)
λp=hmpvp (2)
vp=3ve (3)
Substituting (3) into (2)⇒
λp=hmp3ve (4)
Dividing (4) by (3)⇒
λpλe=hmp3ve.meveh=1.8×10−4
∴me3mp=1.8×10−4
memp=5.4×10−4
This ratio is 5.39522×10−4 for a neutron and 5.36099×104 for a proton, so a neutron seems to be the most likely candidate for the particle in question, though I guess there could be others.
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