A natural gas was containing mixture of methaneand ethane only. On complete combustion of10 litres of gas at STP, the heat evolvedwas 474.6 kJ. Assuming DHcombCH4(g)= –894 kJ/mol and DHcombC2H6(g) = –1500 kJ/mol,the percentage of CH4 and C2H6 will berespectively
nkc , 6 Years ago
Grade 11
1 Answers
Sonu Dulat
Last Activity: 6 Years ago
Let ch4 =x such that C2h6=10-x ltr respSo. Moles of ch4=x/22.4; moles of C2h6=10-x/22.4ATQ(-894*x/22.4)-(1500*10-x/22.4)=-474.6After solving moles of ch4 (x)=7.23 so %=72.3% of C2h6=27.7
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