MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping
Menu
Grade: 12th pass
        A mole ratio of pentane and hexane in a solution in1:4 the vapour pressure of pure pentane and hexane are 400 and 120nm of Hg calculate the mole fraction of pentane in vapour phase?
10 months ago

Answers : (1)

Arun
14829 Points
							

Let the pentane be 1 mole and hexane be 4 mole.
Total number of moles of pentane and hexane in mixture = 1 + 4 = 5 mol 
Mole fraction of pentane in solution = 1/5
Mole fraction of hexane in solution = 4/5
Total pressure of solution :

Ps = XP PPo + XH PHo 
    = 1/5 (400 mm Hg) + 4/5 (120 mm Hg)
   = 80 mm Hg + 96 mm Hg
  = 176 mm Hg  

Mole fraction of pentane in vapour phase = XP PPo/ Ps ​
                                                                 = 80 / 176
                                                                 = 0.45454

 

Regards

Arun (askIITians forum expert)

10 months ago
Think You Can Provide A Better Answer ?
Answer & Earn Cool Goodies

Get Extra Rs. 1,590 off

COUPON CODE: SELF10


Course Features

  • 731 Video Lectures
  • Revision Notes
  • Previous Year Papers
  • Mind Map
  • Study Planner
  • NCERT Solutions
  • Discussion Forum
  • Test paper with Video Solution


Course Features

  • 141 Video Lectures
  • Revision Notes
  • Test paper with Video Solution
  • Mind Map
  • Study Planner
  • NCERT Solutions
  • Discussion Forum
  • Previous Year Exam Questions


Get Extra Rs. 276 off

COUPON CODE: SELF10

Ask Experts

Have any Question? Ask Experts

Post Question

 
 
Answer ‘n’ Earn
Attractive Gift
Vouchers
To Win!!! Click Here for details