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Let the pentane be 1 mole and hexane be 4 mole.Total number of moles of pentane and hexane in mixture = 1 + 4 = 5 mol Mole fraction of pentane in solution = 1/5Mole fraction of hexane in solution = 4/5Total pressure of solution :Ps = XP PPo + XH PHo = 1/5 (400 mm Hg) + 4/5 (120 mm Hg) = 80 mm Hg + 96 mm Hg = 176 mm Hg
Mole fraction of pentane in vapour phase = XP PPo/ Ps = 80 / 176 = 0.45454
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Arun (askIITians forum expert)
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