MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping
Menu
Grade: 10
        A mixture of 0.3 moles of hydrogen and 0.3 moles of iodine are allowed to react in 10 litre evacuated flask at 500 degree Celsius. The reaction is H2 + l2 2HI .The value of k is found to be 64 .The amount of iodine present at equilibrium is?
10 months ago

Answers : (1)

Arun
14776 Points
							
Dear student
 
At equilibrium
 
H2.      +        I2 -----> 2HI
(0.3-x).     (0.3-x).       2x
Now
 
Kc = (2x)²/(0.3-x)(0.3-x)
 
On solving
x = 0.24
 
Hence amount remained at equlibrium = 0.3 - 0.24 = 0.06 mol
10 months ago
Think You Can Provide A Better Answer ?
Answer & Earn Cool Goodies

Get Extra Rs. 1,590 off

COUPON CODE: SELF10


Course Features

  • 731 Video Lectures
  • Revision Notes
  • Previous Year Papers
  • Mind Map
  • Study Planner
  • NCERT Solutions
  • Discussion Forum
  • Test paper with Video Solution


Course Features

  • 141 Video Lectures
  • Revision Notes
  • Test paper with Video Solution
  • Mind Map
  • Study Planner
  • NCERT Solutions
  • Discussion Forum
  • Previous Year Exam Questions


Get Extra Rs. 276 off

COUPON CODE: SELF10

Ask Experts

Have any Question? Ask Experts

Post Question

 
 
Answer ‘n’ Earn
Attractive Gift
Vouchers
To Win!!! Click Here for details