A mixture of 0.3 moles of hydrogen and 0.3 moles of iodine are allowed to react in 10 litre evacuated flask at 500 degree Celsius. The reaction is H2 + l2 2HI .The value of k is found to be 64 .The amount of iodine present at equilibrium is?
Hadiya
8 Years agoGrade 10
1 Answer
Arun
Approved Tutor Answer8 Years ago
Dear student
At equilibrium
H2. + I2 -----> 2HI
(0.3-x). (0.3-x). 2x
Now
Kc = (2x)²/(0.3-x)(0.3-x)
On solving
x = 0.24
Hence amount remained at equlibrium = 0.3 - 0.24 = 0.06 mol