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A metal exist in FCC structure with an edge length of 200pm calculate the nearest neighbour distance and radius of atom

Akib Javid , 8 Years ago
Grade 12
anser 1 Answers
Vikas TU

Last Activity: 8 Years ago

Nearest distance would be b/w the corner atom and the face atom and that is equals to => a/root(2) = 2r
where a is the edge length.
Therfore, r = a/2*root(2) => 200/2root(2) => 100/root(2) => 50root(2) pm. 

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